regex - how to print previous string after selecting specific string python -

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i want find word appear before keyword (specified , searched me) , print out result. tried below code gives me after words not before...

    str = "phone has better display, speaker. phone has average display"     p1 = re.search(r"(display>=?)(.*)", str)     if p1 none:        return none     return p1.groups()

this code gives me 

    , speaker. phone has average display

but want 

    better,average

you can use positive lookahead, findall instead of search:

>>> p = re.compile(r'(\w+)\s+(?=display)') >>> p.findall(str) ['better', 'average']

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