python - Square root calculation using bisection -

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i have following code should find square root using bisection, reason won't. when want find square root of 9 4.5. 

y = float(input('enter number want find square root of: ')) z = y x = 0 ans = 0  while abs(ans**2 - abs(y)) > 0.0001 , ans <= x:     ans = (x + y) / 2.0      if ans**2 < z:         x = ans     else:         y = ans   print 'the square root of', z, 'is', ans

you need check if ans <= y, because y right border in case. need compare ans**2 absolute value of z, not y, because changing y inside loop:

while abs(ans**2 - abs(z)) > 0.00001 , ans <= y:        ans = (x + y) / 2.0      if ans**2 < z:         x = ans     else:         y = ans

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