python - How to convert "01 January 2016" to UTC ISO format? -

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so have following string : " 01 january 2016" utc iso date format ?

i'm using arrow module , following code, it's full of errors, , thinking may be, there smaller more elegent solution python encourages elegant , easier ways things, anyways here's code : 

updatestr = " 01 january 2016" #note space @ beginning datelist = updatestr.split[' '] datedict = {"day" : datelist[1],"month": months.index(datelist[2])+1, "year" : datelist[3]} datestr = str(datedict['day']) + "-" + str(datedict["month"]) + "-" + str(datedict["year"]) dateiso = arrow.get(datestr, 'yyyy-mm-dd hh:mm:ss')

please me have convert utc iso formats, months list of months in year .

you can use datetime:

>>> updatestr = " 01 january 2016" >>> import datetime dt >>> dt.datetime.strptime(updatestr, " %d %b %y") datetime.datetime(2016, 1, 1, 0, 0) >>> _.isoformat() '2016-01-01t00:00:00'

keep in mind 'naive' object without timezone. check out pytz deal timezones elegantly, or add appropriate utcoffset datetime object utc.


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