java - How to check the precision of Float -

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i have float one:

float f = float.valueof("9.222333999444555666"); system.out.println(f);  //prints 9.222334

is there way count number of digits after . sign without using regex: f.tostring().split("\\.")[1].length()?

simply convert value string , place of decimal point.

string s = "" + f; int = s.indexof(".") system.out.println("the number of digits after decimal point " + s.length()-i-1

edit: read op's comment , doubt how round off float. question answered here: format float n decimal places

for quick reference, use this: string.format("%.2f", f). have understand java's float , double not have methods , attributes manipulating precision after decimal point. there several reasons java this, should remember convert float , double string, manipulate them want , convert back.


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