shell - ZSH: Call in-built function from zsh function that uses the same name -

i use zsh , extend in-built cd function. i'd when call cd, changes directly , lists content of directory.

function cd() {     cd $1     ls . } 

i'd have expected code work, turns out, call cd refers function definition, resulting in infinite loop.

is there work-around solve problem, apart choosing different name function?

update

strangely enough, worked

function cd() {     `echo $1`     ls . } 

no idea why.

in order use builtin commands within functions of same name, or anywhere else matter, can use builtin precommand modifier:

function cd() {     builtin cd $1     ls . } 

builtin command tells zsh use builtin name command instead of alias, function or external command of same name. if such builtin not exist error message printed.

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for cases want use external command instead of alias, builtin or function of same name, can use command precommand modifier. example:

command echo foobar 

this use binary echo (most /bin/echo) instead of zsh's builtin echo.

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unlike functions builtin , command not necessary aliases prevent recursions. while possible use alias in alias definition

% alias xx="echo x:" % alias yy="xx y:" % yy foobar y: x: foobar 

each alias name expanded once. on second occurence alias not expanded , function, builtin or external command used.

% alias echo="echo echo:" % echo foobar echo: foobar % alias xx="yy x:" % alias yy="xx y:" % xx foobar zsh: command not found: xx 

of course, can still use builtin or command in aliases, if want prevent use of alias, or if want use builtin or external command specifically. example:

alias echo="command echo" 

with binary echo used instead of builtin.